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Geometry and Measurement · Shape and Space · Lesson 9

Constructing Angles of 15° and 75°

Once you can make 60°, 90° and bisect an angle, a whole family of angles opens up. In this lesson you will use bisecting and adding to construct 15° and 75°, and you will learn to plan a route before you pick up your compasses.

NaCCA B7.3.1.2.6 ⏱ about 45 min

By the end you will be able to

  • ✔Construct 15° by bisecting 30°, which is itself got by bisecting 60°.
  • ✔Construct 75° by bisecting the gap between 60° and 90°.
  • ✔Construct and bisect an angle of 75°, and find the size of each half.
  • ✔Plan which constructions to combine to make a required angle.

Key words

Bisect
To cut into two equal parts.
Complementary angles
Two angles that add up to 90°.
Supplementary angles
Two angles that add up to 180°.
Vertex
The point where two arms of an angle meet.
Curriculum reference

Content standard: B7.3.1.2 Demonstrate how to construct a perpendicular to a line from a given point, bisect a line, bisect angles, and construct angles of the following sizes: 30°, 45°, 60°, 75° and 90°.

Indicator: Construct angles whose measures are 15° and 75°.

Starter

The tailor's angles

A tailor in Aboabo makes a pattern for a shirt collar with a point of 75°, and he wants a matching tab of 15° so that the two pieces fit together into a right-angled corner. He has no protractor with him, only chalk, a string and a pair of compasses. Can you work out which constructions he needs, and in which order?

1. Building new angles from old ones

You can already construct 60°, 30°, 90° and 45°. A clever builder does not learn a new method for every angle. She uses two ideas over and over: bisect an angle to halve it, and add or subtract angles that are next to each other. With these two ideas you can make 15° and 75° as well.

Angle you wantRouteWorking
15°Bisect 30°30° ÷ 2 = 15°
75° (route 1)Add 15° to 60°60° + 15° = 75°
75° (route 2)Bisect the gap between 60° and 90°60° + (30° ÷ 2) = 75°
7½°Bisect 15°15° ÷ 2 = 7.5°

Notice how neatly the angles link together: 60° → 30° → 15° → 7½°. Each is exactly half of the one before. So 15° needs three constructions: 60°, then bisect to 30°, then bisect to 15°. These are the three quick constructions from the last lessons.

2. Constructing 15°

The curriculum says: Construct an angle of 15° by bisecting an angle of 30°, which in turn is got by bisecting 60°. Follow the steps carefully with a sharp pencil. Because you bisect twice, small errors can grow, so draw your arcs lightly and accurately.

  1. 1Construct angle AOB = 60° (an arc from O cuts the line at A; the same radius from A cuts the arc at B).
  2. 2Bisect angle AOB: arcs from A and B (same opening) cross at P. Join OP. Angle AOP = 30°.
  3. 3Bisect angle AOP: draw an arc from the point where OP meets the first arc and another from A. They cross at G.
  4. 4Join O to G. Angle AOG = 30° ÷ 2 = 15°.

▶ Watch the angle shrink: 60° to 30° to 15°. Each bisecting uses two equal arcs.

To verify, place the protractor on O. The line OG should be at 15°. If the reading is 14° or 16°, that is fine. If it is 12° or 18°, check your arcs.

3. Constructing 75°

Seventy-five degrees is a very useful angle: it is 60° + 15°, or 90° − 15°. The curriculum method uses the right angle: construct 90° at O, construct 60° beside it, and then bisect the gap between 60° and 90°.

  1. 1At O, construct 60° (point B on the arc) and 90° (point D on the arc). The angle between OB and OD is 30°.
  2. 2Bisect angle BOD: with the compass on B and then on D (same opening), draw arcs that cross at F.
  3. 3Join O to F. Because OF lies half way between 60° and 90°, angle AOF = 60° + 15° = 75°.

▶ Notice that 75° = 60° + 15°: the bisector OF sits half way between the 60° line and the 90° line.

OF is exactly halfway between 60° and 90°, since (60 + 90) ÷ 2 = 75.
LineAngle from OA
OB60°
OF (the new bisector)75°
OD90°

Constructing and bisecting 75°. Curriculum example 4 asks you to construct 75° and then bisect it. Bisecting 75° gives 75° ÷ 2 = 37.5° (that is 37½°). Use the standard bisector steps from the vertex.

4. Checking, combining and using

Because 75° and 15° add up to 90°, they are complementary angles. This gives a quick check: if you have constructed 75° and then 15° on the other side of the same arm, the two together must form a right angle.

PairSumMeaning
75° + 15°90°Complementary: they form a right angle
75° + 105°180°Supplementary: they lie on a straight line
15° × 690°Six 15° angles make a right angle
15° × 12180°Twelve 15° angles make a straight line

Another useful fact: a clock face is divided into 12 hours, so each hour mark is 360° ÷ 12 = 30° from the next. Bisecting that gives 15°, the angle between the hour hand and the next half-hour position.

Worked examples

Try each one yourself first, then open the solution and compare every step.

Example 1

Construct 15°

Construct an angle of 15° by bisecting a 30° angle.

▶ Count how many times the angle is bisected.

Show the solution
  1. Step 1Construct 60° at O (angle AOB).
  2. Step 2Bisect it: arcs from A and B cross at P. Angle AOP = 30°.
  3. Step 3Bisect angle AOP: arcs cross at G. Join OG.
  4. Step 4Angle AOG = 30° ÷ 2 = 15°.

Answer: Angle AOG = 15°

Example 2

Construct 75°

Construct an angle of 75° at O on a line.

▶ Find the lines at 60° and 90°. Where does the bisector fall?

Show the solution
  1. Step 1Construct 60° and 90° at O: OB is at 60° and OD is at 90°. The gap BOD is 90° − 60° = 30°.
  2. Step 2Bisect angle BOD: arcs from B and D cross at F. Join OF.
  3. Step 3Angle BOF = 30° ÷ 2 = 15°, so angle AOF = 60° + 15° = 75°.

Answer: Angle AOF = 75°

Example 3

Construct and bisect 75°

Construct angle ABC = 75° and bisect it. What is the size of each half?
Show the solution
  1. Step 1Construct 75° as in the last example.
  2. Step 2Bisect it: draw an arc from the vertex cutting both arms and two equal arcs from those points.
  3. Step 3Each half = 75° ÷ 2 = 37.5°.

Answer: 37.5° (37½°) each

Example 4

Complementary check

Akosua constructs angle AOF = 75°. What angle must be added to complete a right angle at O?
Show the solution
  1. Step 1A right angle is 90°.
  2. Step 290° − 75° = 15°.
  3. Step 3Check: 75° + 15° = 90° ✓.

Answer: 15°

Example 5

Angles on a straight line

Two angles of 75° each are drawn side by side on a straight line, with a third angle x completing the line. Find x.
Show the solution
  1. Step 1Angles on a straight line add up to 180°.
  2. Step 275° + 75° = 150°.
  3. Step 3x = 180° − 150° = 30°.

Answer: x = 30°

Summary

  • 15° is half of 30°, which is half of 60°: construct 60° and bisect twice.
  • 75° = 60° + 15° = 90° − 15°: bisect the gap between 60° and 90°.
  • 75° and 15° are complementary, since 75° + 15° = 90°.
  • Bisecting 75° gives 37.5°; bisecting 15° gives 7.5°.
  • Plan the route first, draw arcs lightly, and check with a protractor.

Practice: 15 questions

5 easy, 5 medium, 5 hard. Each one is marked straight away, with a full worked solution.

You can practise without an account, but sign up free or sign in to save your progress.

1 easy
A 30° angle is bisected. What is each half, in degrees?
2 easy
Find 60° + 15°, in degrees.
3 easy
Which angle is bisected to give 15°?
4 easy
Find 90° − 15°, in degrees.
5 easy
A 15° angle is bisected. What is each half, in degrees?
6 medium
OB is at 60° and OD is at 90°. What is the size of angle BOD, in degrees?
7 medium
Which is the correct set of constructions for 15°?
8 medium
Angle ABC = 75° is bisected. What is each half, in degrees?
9 medium word problem
On a straight road line, a signpost makes an angle of 75° with the road on one side. What is the angle on the other side of the signpost, in degrees?
10 medium
How many 15° angles make a right angle?
11 hard
Which of these is NOT a correct way to obtain 75°?
12 hard word problem
Esi constructs 15° by bisecting twice from 60°.
  1. (a) What is the size of the angle after the first bisecting, in degrees?

  2. (b) What is the size of the angle after the second bisecting, in degrees?

  3. (c) What angle is 75° plus Esi's 15°, in degrees?

13 hard word problem
Ama constructs angle AOF = 75° from a right angle AOD. What is the size of angle FOD, in degrees?
14 hard
Why does bisecting the gap between the 60° line and the 90° line give 75°?
15 hard word problem
Two angles of 75° are placed side by side on a straight line. What is the third angle needed to complete the line, in degrees?