Geometry and Measurement · Shape and Space · Lesson 9
Constructing Angles of 15° and 75°
Once you can make 60°, 90° and bisect an angle, a whole family of angles opens up. In this lesson you will use bisecting and adding to construct 15° and 75°, and you will learn to plan a route before you pick up your compasses.
By the end you will be able to
- ✔Construct 15° by bisecting 30°, which is itself got by bisecting 60°.
- ✔Construct 75° by bisecting the gap between 60° and 90°.
- ✔Construct and bisect an angle of 75°, and find the size of each half.
- ✔Plan which constructions to combine to make a required angle.
Key words
- Bisect
- To cut into two equal parts.
- Complementary angles
- Two angles that add up to 90°.
- Supplementary angles
- Two angles that add up to 180°.
- Vertex
- The point where two arms of an angle meet.
Curriculum reference
Content standard: B7.3.1.2 Demonstrate how to construct a perpendicular to a line from a given point, bisect a line, bisect angles, and construct angles of the following sizes: 30°, 45°, 60°, 75° and 90°.
Indicator: Construct angles whose measures are 15° and 75°.
Starter
The tailor's angles
A tailor in Aboabo makes a pattern for a shirt collar with a point of 75°, and he wants a matching tab of 15° so that the two pieces fit together into a right-angled corner. He has no protractor with him, only chalk, a string and a pair of compasses. Can you work out which constructions he needs, and in which order?
1. Building new angles from old ones
You can already construct 60°, 30°, 90° and 45°. A clever builder does not learn a new method for every angle. She uses two ideas over and over: bisect an angle to halve it, and add or subtract angles that are next to each other. With these two ideas you can make 15° and 75° as well.
| Angle you want | Route | Working |
|---|---|---|
| 15° | Bisect 30° | 30° ÷ 2 = 15° |
| 75° (route 1) | Add 15° to 60° | 60° + 15° = 75° |
| 75° (route 2) | Bisect the gap between 60° and 90° | 60° + (30° ÷ 2) = 75° |
| 7½° | Bisect 15° | 15° ÷ 2 = 7.5° |
Notice how neatly the angles link together: 60° → 30° → 15° → 7½°. Each is exactly half of the one before. So 15° needs three constructions: 60°, then bisect to 30°, then bisect to 15°. These are the three quick constructions from the last lessons.
2. Constructing 15°
The curriculum says: Construct an angle of 15° by bisecting an angle of 30°, which in turn is got by bisecting 60°. Follow the steps carefully with a sharp pencil. Because you bisect twice, small errors can grow, so draw your arcs lightly and accurately.
- 1Construct angle AOB = 60° (an arc from O cuts the line at A; the same radius from A cuts the arc at B).
- 2Bisect angle AOB: arcs from A and B (same opening) cross at P. Join OP. Angle AOP = 30°.
- 3Bisect angle AOP: draw an arc from the point where OP meets the first arc and another from A. They cross at G.
- 4Join O to G. Angle AOG = 30° ÷ 2 = 15°.
▶ Watch the angle shrink: 60° to 30° to 15°. Each bisecting uses two equal arcs.
To verify, place the protractor on O. The line OG should be at 15°. If the reading is 14° or 16°, that is fine. If it is 12° or 18°, check your arcs.
3. Constructing 75°
Seventy-five degrees is a very useful angle: it is 60° + 15°, or 90° − 15°. The curriculum method uses the right angle: construct 90° at O, construct 60° beside it, and then bisect the gap between 60° and 90°.
- 1At O, construct 60° (point B on the arc) and 90° (point D on the arc). The angle between OB and OD is 30°.
- 2Bisect angle BOD: with the compass on B and then on D (same opening), draw arcs that cross at F.
- 3Join O to F. Because OF lies half way between 60° and 90°, angle AOF = 60° + 15° = 75°.
▶ Notice that 75° = 60° + 15°: the bisector OF sits half way between the 60° line and the 90° line.
| Line | Angle from OA |
|---|---|
| OB | 60° |
| OF (the new bisector) | 75° |
| OD | 90° |
Constructing and bisecting 75°. Curriculum example 4 asks you to construct 75° and then bisect it. Bisecting 75° gives 75° ÷ 2 = 37.5° (that is 37½°). Use the standard bisector steps from the vertex.
4. Checking, combining and using
Because 75° and 15° add up to 90°, they are complementary angles. This gives a quick check: if you have constructed 75° and then 15° on the other side of the same arm, the two together must form a right angle.
| Pair | Sum | Meaning |
|---|---|---|
| 75° + 15° | 90° | Complementary: they form a right angle |
| 75° + 105° | 180° | Supplementary: they lie on a straight line |
| 15° × 6 | 90° | Six 15° angles make a right angle |
| 15° × 12 | 180° | Twelve 15° angles make a straight line |
Another useful fact: a clock face is divided into 12 hours, so each hour mark is 360° ÷ 12 = 30° from the next. Bisecting that gives 15°, the angle between the hour hand and the next half-hour position.
Worked examples
Try each one yourself first, then open the solution and compare every step.
Example 1
Construct 15°
▶ Count how many times the angle is bisected.
Show the solution
- Step 1Construct 60° at O (angle AOB).
- Step 2Bisect it: arcs from A and B cross at P. Angle AOP = 30°.
- Step 3Bisect angle AOP: arcs cross at G. Join OG.
- Step 4Angle AOG = 30° ÷ 2 = 15°.
Answer: Angle AOG = 15°
Example 2
Construct 75°
▶ Find the lines at 60° and 90°. Where does the bisector fall?
Show the solution
- Step 1Construct 60° and 90° at O: OB is at 60° and OD is at 90°. The gap BOD is 90° − 60° = 30°.
- Step 2Bisect angle BOD: arcs from B and D cross at F. Join OF.
- Step 3Angle BOF = 30° ÷ 2 = 15°, so angle AOF = 60° + 15° = 75°.
Answer: Angle AOF = 75°
Example 3
Construct and bisect 75°
Show the solution
- Step 1Construct 75° as in the last example.
- Step 2Bisect it: draw an arc from the vertex cutting both arms and two equal arcs from those points.
- Step 3Each half = 75° ÷ 2 = 37.5°.
Answer: 37.5° (37½°) each
Example 4
Complementary check
Show the solution
- Step 1A right angle is 90°.
- Step 290° − 75° = 15°.
- Step 3Check: 75° + 15° = 90° ✓.
Answer: 15°
Example 5
Angles on a straight line
Show the solution
- Step 1Angles on a straight line add up to 180°.
- Step 275° + 75° = 150°.
- Step 3x = 180° − 150° = 30°.
Answer: x = 30°
Summary
- 15° is half of 30°, which is half of 60°: construct 60° and bisect twice.
- 75° = 60° + 15° = 90° − 15°: bisect the gap between 60° and 90°.
- 75° and 15° are complementary, since 75° + 15° = 90°.
- Bisecting 75° gives 37.5°; bisecting 15° gives 7.5°.
- Plan the route first, draw arcs lightly, and check with a protractor.
Practice: 15 questions
5 easy, 5 medium, 5 hard. Each one is marked straight away, with a full worked solution.
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