Geometry and Measurement · Shape and Space · Lesson 7
Constructing Angles of 90° and 45°
Every square corner in a building, every set square in your geometry box and every mitred picture frame depends on the right angle (90°) and on 45°. In this lesson you will build both with compasses and a ruler, so that you understand how they are made and can check them.
By the end you will be able to
- ✔Construct an angle of 90° using compasses and a ruler and verify it with a protractor.
- ✔Raise a perpendicular at a point on a line.
- ✔Construct an angle of 45° by bisecting 90°.
- ✔Construct 45° angles with given arm lengths.
Key words
- Right angle
- An angle of exactly 90°, a quarter turn.
- Perpendicular
- Meeting at 90°.
- Bisect
- To cut into two equal parts.
- Arc
- A part of a circle drawn with compasses.
- Mitre
- A joint cut at 45° so that two pieces form a right-angled corner.
Curriculum reference
Content standard: B7.3.1.2 Demonstrate how to construct a perpendicular to a line from a given point, bisect a line, bisect angles, and construct angles of the following sizes: 30°, 45°, 60°, 75° and 90°.
Indicator: Construct angles of 90° and 45°.
Starter
The perfect corner
Before pouring concrete for a new shop at Kejetia Market, the mason must be sure the corner is a perfect right angle. If it is only a few degrees wrong, the whole building will lean when it is built up. He has no protractor, only strings, pegs and compasses. How does he make sure the corner is 90°? And how does a carpenter cut a perfect 45° mitre? Let's find out.
1. The right angle is everywhere
Look at the corner of your classroom, the corner of this page, the corner of a window frame or a Ghana Cedi note. All of them make a right angle, which measures exactly 90°. Builders need right angles so that walls stand straight. If a corner is even 2° out, a long wall drifts a long way off line.
A protractor or a set square can give you a 90° angle quickly, but they can be inaccurate or unavailable. In this lesson you will build a 90° angle using only a pair of compasses and a ruler. Then you will cut it in half to get 45°. Half of 90° is 45°, so a 45° angle is simply a bisected right angle.
| Angle | Name | How we get it by construction |
|---|---|---|
| 60° | acute | Two equal arcs (equilateral triangle) |
| 120° | obtuse | Two 60° angles side by side |
| 90° | right | Bisect the gap between 60° and 120° |
| 45° | acute | Bisect a 90° angle |
2. Constructing an angle of 90°
The syllabus asks you to raise a perpendicular at a point on a line, which is the same as building a 90° angle. We build it from the 60° and 120° angles that you already know how to make with equal arcs. The key idea is that 90° is exactly halfway between 60° and 120°.
- 1Draw a straight line. Mark the point O on it where the angle will be.
- 2With the compass point on O, draw a large arc that cuts the line at A.
- 3Keep the same opening. Put the compass point on A and cut the arc at B. Angle AOB = 60°.
- 4Keep the same opening. Put the compass point on B and cut the arc again at C. Angle AOC = 120°, so angle BOC = 60°.
- 5From B and then from C (same opening, any convenient width), draw arcs that cross at D. D is exactly between B and C.
- 6Join O to D. Angle AOD = 60° + 30° = 90°.
▶ Notice that BOC is a 60° angle. Bisecting it gives 30°, and 60° + 30° = 90°.
Check with a protractor: place the centre of the protractor on O and the baseline along OA. The line OD should pass through 90° (within 1°).
Another way: a perpendicular at a point. A line PQ is perpendicular to AB at P if the angle at P is 90°. Put the compass point on P and cut the line at A and B so that PA = PB. Open the compass wider and draw arcs from A and from B above P so they cross at Q. Join P and Q. This is just the perpendicular bisector method applied to the segment AB, because P is the midpoint of AB.
▶ Because PA = PB, P is the midpoint of AB. The line PQ is its perpendicular bisector, so angle QPB = 90°.
3. Constructing an angle of 45°
Forty-five degrees is half of a right angle, so we begin with the 90° construction and then bisect it. The bisecting steps are the ones you used in the last lesson: an arc that cuts both arms and two equal arcs that cross.
- 1Construct a 90° angle AOD as shown above.
- 2With the compass on O, draw an arc cutting OA at X and OD at Y.
- 3With the compass on X and then on Y (same opening), draw arcs that cross at E.
- 4Join O to E. Angle AOE = 90° ÷ 2 = 45°.
▶ First the 90° angle is built, then it is bisected. Notice that angle AOE and angle EOD are both 45°.
Fixing the arm lengths. Some exercises say: Construct angle AOB = 45° such that OA = 5 cm and OB = 6 cm. This simply fixes the length of the arms. After you construct the 45° angle, measure 5 cm along one arm from O to mark A, and 6 cm along the other arm to mark B. The angle does not change when the arms are longer or shorter.
4. Using right angles and 45° angles
Right angles and 45° angles are used in many trades. A tailor cuts cloth on the bias (45°) so that it stretches along the diagonal. A mason makes sure the foundation corner is 90°. A carpenter cuts a mitre joint at 45° to join two pieces of picture frame so that they form a 90° corner.
| Task | Angle | Key idea |
|---|---|---|
| Square corner of a wall | 90° | Quarter turn |
| Mitre joint of a picture frame | 45° each side | Two 45° cuts make a 90° corner |
| Diagonal of a square | 45° to each side | The diagonal bisects the right angle |
| Tiles laid diagonally | 45° | Tile edges at half a right angle |
There is a very useful pattern. If you bisect a right angle you get 45°. If you bisect again you get 22.5°. Four right angles fit around a point (4 × 90° = 360°), and four 45° angles fit in a straight line (4 × 45° = 180°).
Worked examples
Try each one yourself first, then open the solution and compare every step.
Example 1
Construct 90° at O
▶ Watch where the 60° and 120° points B and C are placed before D is found.
Show the solution
- Step 1Draw a line and mark O. With the compass on O, draw an arc cutting the line at A.
- Step 2With the same opening, step off from A to B and from B to C on the arc. Angle AOB = 60° and AOC = 120°.
- Step 3Bisect angle BOC: arcs from B and C cross at D. Join OD.
- Step 4Angle AOD = 60° + 30° = 90°. The protractor reads 90°.
Answer: Angle AOD = 90°
Example 2
A perpendicular at a point
▶ P is the midpoint of the marked segment. Which construction from the previous lesson is this?
Show the solution
- Step 1Compass on P: mark A′ and B′ on the line so PA′ = PB′.
- Step 2Open the compass wider. From A′ and then from B′ draw arcs above P that cross at Q.
- Step 3Join P and Q. Angle QPB′ = 90°.
Answer: PQ is perpendicular to AB at P
Example 3
Construct 45°
▶ Follow the construction: where is the 90° angle bisected?
Show the solution
- Step 1Construct angle AOD = 90°.
- Step 2Draw an arc from O cutting OA at X and OD at Y.
- Step 3Draw equal arcs from X and Y that cross at E. Join OE.
- Step 4Angle AOE = 90° ÷ 2 = 45°.
Answer: Angle AOE = angle EOD = 45°
Example 4
Angle with given arm lengths
Show the solution
- Step 1Draw a line and mark O. Construct 90° and bisect it to get a 45° angle at O.
- Step 2On the base arm measure 5 cm from O and label the point A.
- Step 3On the 45° arm measure 6 cm from O and label the point B.
- Step 4Join A to B to complete triangle OAB. Angle AOB = 45°, and the arms are 5 cm and 6 cm.
Answer: Angle AOB = 45° with OA = 5 cm and OB = 6 cm
Example 5
Is this corner square?
Show the solution
- Step 1The 3-4-5 rule says a corner is square when sides in the ratio 3 : 4 : 5 are used.
- Step 26 : 8 : 10 = (3 × 2) : (4 × 2) : (5 × 2), so the ratio is 3 : 4 : 5.
- Step 3Check: 6² + 8² = 36 + 64 = 100 = 10² ✓.
Answer: Yes, the corner is a right angle (90°)
Summary
- A right angle is 90°; construct it by building 60° and 120° with equal arcs and bisecting the gap between them.
- A perpendicular at a point P on a line can be raised by marking equal distances on each side of P and crossing arcs above.
- 45° = half of 90°, so bisect a right angle to obtain it.
- Arm lengths such as OA = 5 cm and OB = 6 cm are measured after the angle is constructed.
- Check each construction with a protractor, allowing for an error of 1° or so.
Practice: 15 questions
5 easy, 5 medium, 5 hard. Each one is marked straight away, with a full worked solution.
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